Number Patterns for C, Java, and Python Programming

For your interview preparation, I created all-in-one solutions for different varieties of number patterns in C, Java, and Python.

1. Pattern: Descending Number Triangle

Expected output:

12345
1234
123
12
1

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows
    for (int i = 5; i >= 1; i--) {
        // Inner loop for printing numbers from 1 to i
        for (int j = 1; j <= i; j++) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows
        for (int i = 5; i >= 1; i--) {
            // Inner loop for printing numbers from 1 to i
            for (int j = 1; j <= i; j++) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows
for i in range(5, 0, -1):
    # Inner loop for printing numbers from 1 to i
    for j in range(1, i + 1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

2. Pattern: Descending Number Triangle

Expected output:

54321
4321
321
21
1

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 5 down to 1)
    for (int i = 5; i >= 1; i--) {
        // Inner loop to print numbers from i down to 1
        for (int j = i; j >= 1; j--) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 5 down to 1)
        for (int i = 5; i >= 1; i--) {
            // Inner loop to print numbers from i down to 1
            for (int j = i; j >= 1; j--) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 5 down to 1)
for i in range(5, 0, -1):
    # Inner loop to print numbers from i down to 1
    for j in range(i, 0, -1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

3. Pattern: Descending Number Triangle (Modified)

Expected output:

12345
2345
345
45
5

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print numbers starting from i to 5
        for (int j = i; j <= 5; j++) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print numbers starting from i to 5
            for (int j = i; j <= 5; j++) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print numbers starting from i to 5
    for j in range(i, 6):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

4. Pattern: Descending Number Triangle (Modified)

Expected output:

54321
5432
543
54
5

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 5 down to 1)
    for (int i = 5; i >= 1; i--) {
        // Inner loop to print numbers starting from 5 down to i
        for (int j = 5; j >= 6 - i; j--) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 5 down to 1)
        for (int i = 5; i >= 1; i--) {
            // Inner loop to print numbers starting from 5 down to i
            for (int j = 5; j >= 6 - i; j--) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 5 down to 1)
for i in range(5, 0, -1):
    # Inner loop to print numbers starting from 5 down to i
    for j in range(5, 6 - i, -1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

5. Pattern: Ascending Number Triangle

Expected output:

1
21
321
4321
54321

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print numbers starting from i down to 1
        for (int j = i; j >= 1; j--) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print numbers starting from i down to 1
            for (int j = i; j >= 1; j--) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print numbers starting from i down to 1
    for j in range(i, 0, -1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

6. Pattern: Ascending Number Triangle

Expected output:

1
12
123
1234
12345

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print numbers from 1 to i
        for (int j = 1; j <= i; j++) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print numbers from 1 to i
            for (int j = 1; j <= i; j++) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print numbers from 1 to i
    for j in range(1, i + 1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

7. Pattern: Descending Number Triangle (Modified)

Expected output:

5
54
543
5432
54321

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print numbers starting from 5 down to (5 - i + 1)
        for (int j = 5; j >= 6 - i; j--) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print numbers starting from 5 down to (5 - i + 1)
            for (int j = 5; j >= 6 - i; j--) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print numbers starting from 5 down to (5 - i + 1)
    for j in range(5, 6 - i, -1):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

8. Pattern: Modified Ascending Number Triangle

Expected output:

5
45
345
2345
12345

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 5; i >= 1; i--) {
        // Inner loop to print numbers starting from i to 5
        for (int j = i; j <= 5; j++) {
            printf("%d", j); // Print the current number
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 5 down to 1)
        for (int i = 5; i >= 1; i--) {
            // Inner loop to print numbers starting from i to 5
            for (int j = i; j <= 5; j++) {
                System.out.print(j); // Print the current number
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 5 down to 1)
for i in range(5, 0, -1):
    # Inner loop to print numbers starting from i to 5
    for j in range(i, 6):
        print(j, end='')  # Print the current number, stay on the same line
    print()  # Move to the next line after each row

9. Pattern: Repetitive Number Triangle

Expected output:

1
22
333
4444
55555

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 1 to 5)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print the number i, i times
        for (int j = 1; j <= i; j++) {
            printf("%d", i); // Print the current number i
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print the number i, i times
            for (int j = 1; j <= i; j++) {
                System.out.print(i); // Print the current number i
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print the number i, i times
    for j in range(i):
        print(i, end='')  # Print the current number i, stay on the same line
    print()  # Move to the next line after each row

10. Pattern: Descending Repetitive Number Triangle

Expected output:

55555
4444
333
22
1

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 5 to 1)
    for (int i = 5; i >= 1; i--) {
        // Inner loop to print the number i, i times
        for (int j = 1; j <= i; j++) {
            printf("%d", i); // Print the current number i
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 5 down to 1)
        for (int i = 5; i >= 1; i--) {
            // Inner loop to print the number i, i times
            for (int j = 1; j <= i; j++) {
                System.out.print(i); // Print the current number i
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 5 down to 1)
for i in range(5, 0, -1):
    # Inner loop to print the number i, i times
    for j in range(i):
        print(i, end='')  # Print the current number i, stay on the same line
    print()  # Move to the next line after each row

11. Pattern:

Expected output:

5
44
333
2222
11111

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 5 down to 1)
    for (int i = 5; i >= 1; i--) {
        // Inner loop to print the number i, i times
        for (int j = 1; j <= i; j++) {
            printf("%d", i); // Print the current number i
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 5 down to 1)
        for (int i = 5; i >= 1; i--) {
            // Inner loop to print the number i, i times
            for (int j = 1; j <= i; j++) {
                System.out.print(i); // Print the current number i
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 5 down to 1)
for i in range(5, 0, -1):
    # Inner loop to print the number i, i times
    for j in range(i):
        print(i, end='')  # Print the current number i, stay on the same line
    print()  # Move to the next line after each row

12. Pattern: Descending Repetitive Number Triangle (Modified)

Expected output:

11111
2222
333
44
5

Solution in C Program:

#include <stdio.h>

int main() {
    // Outer loop for the number of rows (starting from 5 down to 1)
    for (int i = 1; i <= 5; i++) {
        // Inner loop to print the number i, 6 - i times
        for (int j = 1; j <= 6 - i; j++) {
            printf("%d", i); // Print the current number i
        }
        printf("n"); // Move to the next line after each row
    }
    return 0;
}

Solution in Java:

public class NumberPattern {
    public static void main(String[] args) {
        // Outer loop for the number of rows (starting from 1 to 5)
        for (int i = 1; i <= 5; i++) {
            // Inner loop to print the number i, 6 - i times
            for (int j = 1; j <= 6 - i; j++) {
                System.out.print(i); // Print the current number i
            }
            System.out.println(); // Move to the next line after each row
        }
    }
}

Solution in Python:

# Outer loop for the number of rows (starting from 1 to 5)
for i in range(1, 6):
    # Inner loop to print the number i, 6 - i times
    for j in range(6 - i):
        print(i, end='')  # Print the current number i, stay on the same line
    print()  # Move to the next line after each row

Hope you find them helpful for your interview preparation in a good way.

©️ 2025, Number patterns in C, Java, and Python programming language by Rakshit Shah (Author).

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